Question

Q2. (a) In the given figure TP and TQ are two tangents to the circle with
centre 0, touching at A and C respectively. If ZBCQ = 55° and and BAP =
60°, find (i) ZOBA and Z OBC
(4)
(ii) ZAOC (iii) <ATC​

Answer 1

Answer:

Given, ∠POQ=110°

We know,

∠OPT=∠OQT=90°

(Angle between the tangent and the radial line at the point of intersection of the tangent at the circle)

Now, in quadrilateral POQT

Sum of angles=360

∠OPT+∠OQT+∠PTQ+∠POQ=360°

90+90+∠PTQ+110=360

∠PTQ=360−290

∠PTQ=70°

Step-by-step explanation:

hope it helps you #sadsoul