Question

Q2 . A quadratic polynomial, sum and product of whose zeroes are respectively -1 and -12 is​

Answer 1

Given:

Sum of zeroes = (-1)

Product of zeroes = (-12)

To find:

The polynomial satisfying the given conditions

Solution:

The formula for finding the polynomial:

Polynomial = kx^2 - (sum of zeroes)x + (product of zeroes)

=> Polynomial = kx^2 - (-1)x + (-12)

=> kx^2 + x - 12

In a simpler way, you can write the equation as:

x^2 + x - 12

Answer 2

Answer: x² + x - 12

Step by step explanation:

Given:

Sum of zeroes: -1

Product of zeroes: -12

To find: Quadratic polynomial.

We know that,

Every quadratic equations are based on following relation.

p(x) = kx² - (α + β)x + αβ

Here, α and β are the zeroes of the polynomial.

So, as given:

α + β = -1 and αβ = -12

Thus, putting these values in the above equation, we get:

p(x) = x² - (-1)x + (-12)

= x² + x - 12

Thus, x² + x - 12 is the required quadratic polynomial.