Q2.A rectangular metal sheet of length 44 cm and breadth 11 cm is folded along its length to form a cylinder. Find its volume.
Answers
Answer:
We know that the curved surface area of a right circular cylinder with radius r and height h is CSA=2πrh.
It is given that the length of the rectangular sheet is l=44 cm and the height of the sheet is h=20 cm. Since the cylinder is formed among the length, therefore, length of rectangular sheet is equal to circumference of base that is:
l=2πr
⇒44=2×
7
22
×r
⇒r=
2×22
44×7
=7
Therefore, the radius of the rectangular sheet is 7 cm.
We also know that the volume of a right circular cylinder with radius r and height h is V=πr
2
h.
Here, the height is h=20 cm and the radius is r=7 cm, therefore,
V=πr
2
h=
7
22
×(7)
2
×20=
7
22
×49×20=3080 cm
3
Hence, the volume of the cylinder is 3080 cm
3
.
Step-by-step explanation:
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Answer:
Answer:
The volume of the cylinder is 2772 cm^3.
Explanation
Let the radius be = r
we know that the length of the sheet = circumference of the circle
Height of the cylinder = 18 cm
44 = 2r
2 x 22/7 r = 44
r = (44 x 7) / (22 x 2)
r = 7 cm
Volume of cylinder = r^2 .h
=22/7 * 7*7 * 18
= 2772 cm^3
The volume of the cylinder is 2772 cm^3.