Q2.A stone was thrown vertically up with a velocity of 20m/s.If it retards at a rate of 10m/s?.What will be the maximum height reached by the stone? (2)
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1
Solution
Height=1.25m and time =0.5s
Given, initial velocity, u=5ms −1
Final velocity, v=0
Since, u is upward & a is downward, it is a retarded motion.
∴a=−10ms
−2
Height attained by stone, s=?
Time take to attain height, t=?
(i) Using the relation, v
2
−u
2
=2as, we have
s=v
2
−u
2
/2a
=(0)
2
−(5)
2
/2×(−10)=1.25m
(ii) Using the relation, v=u+at
0=5+(−10)t or
t=5/10=0.5s
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Answer:
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Step-by-step explanation:
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