Question

Q2. A stone which is at rest was given an acceration of 25km/hr. If It travels a distance of 75km at 3 hrs. What is the final velocity of the stone??​

Answer 1

Answer:

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Answer 2

Answer:

Let’s begin with a particle with an acceleration a(t) is a known function of time. Since the time derivative of the velocity function is acceleration,

we can take the indefinite integral of both sides, finding

where C1 is a constant of integration. Since

, the velocity is given by

Similarly, the time derivative of the position function is the velocity function,

Thus, we can use the same mathematical manipulations we just used and find

where C2 is a second constant of integration.

We can derive the kinematic equations for a constant acceleration using these integrals. With a(t) = a a constant, and doing the integration in (Figure), we find

If the initial velocity is v(0) = v0, then

Then, C1 = v0 and

which is (Equation). Substituting this expression into (Figure) gives

Doing the integration, we find

If x(0) = x0, we have

so, C2 = x0. Substituting back into the equation for x(t).

Explanation:

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