Question

Q2. A truck is moving with a constant velocity, v = 5 m.s-1. The driver stops for diesel and the truck accelerates forward. After 20 seconds, the driver stops accelerating to maintain a constant velocity, v = 25 m.s-1. What is the truck’s acceleration?​

Answer 1

Answer:

• Truck's acceleration is 1 m/s².

Explanation:

Given,

●Initial velocity, (u) = 5 m/s

●Final velocity, (v) = 25 m/s

●Time interval, (t) = 20 s

From definition, acceleration is given as:

$\purple\bigstar$ a = (v - u)/t

[ Putting values ]

↪a = (25 - 5)/20

↪a = 20/20

↪a = 1 m/s² $\red\bigstar$

Equation of motion:

• v = u + at
• s = ut + 1/2 at²
• v² = u² + 2as

Answer 2

Question :

Q2. A truck is moving with a constant velocity, v = 5 m.s-1. The driver stops for diesel and the truck accelerates forward. After 20 seconds, the driver stops accelerating to maintain a constant velocity, v = 25 m.s-1. What is the truck’s acceleration?​

Given :

• Initial velocity of truck (u) = 5 m/s [After accelerating the constant velocity of truck will work as initial velocity]
• Final velocity of body (v) = 25 m/s [As truck maintains a constant velocity of 25 m/s after stopping acceleration, so it will work as final velocity of truck during constant acceleration]
• Time (t) = 20 s

To find :

• Acceleration of truck

Solution :

Using first equation of motion :

⇒ v = u + at

Where,

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

Substituting values,

⇒ 25 = 5 + a * 20

⇒ 25 - 5 = 20a

⇒ 20 = 20a

⇒ a = 20/20

⇒ a = 1 m/s²

∴ Truck's acceleration is 1 m/s²