Question

Q2. A truck is moving with a constant velocity, v = 5 m.s-1. The driver stops for diesel and the truck accelerates forward. After 20 seconds, the driver stops accelerating to maintain a constant velocity, v = 25 m.s-1. What is the truck’s acceleration?​

Answer 1

Answer :

Initial velocity of truck = 5 m/s

Final velocity of truck = 25 m/s

Time of journey = 20 s

We have to find acceleration of the truck$.$

★ Acceleration is defined as the rate of change of velocity.

• It is a vector quantity having both magnitude as well as direction.
• It can be positive, negative or zero.
• SI unit : m/s²

Mathematically, a = (v - u)/t

→ v - u = at

→ v = u + at

This equation is called first equation of kinematics.

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

By substituting the given values,

➠ v = u + at

➠ 25 = 5 + 20a

➠ 25 - 5 = 20a

➠ a = 20/20

➠ a = 1 m/s²

Answer 2

Explanation:

$\pink{given : } \: \: \: \: \: \: \: \: \: \: \\ \\ u = 5 \: \: m {s}^{ - 1} \\ \\ v = 25 \: \: m {s}^{ - 1} \\ \\ t = 20 \ \: s \: \: \: \: \: \: \: \\ \\ \blue{To \: \: \: find : } \: \: \\ \\ a \\ \\ \green{soluion : } \\ \\ v = u + at \\ \\ a = \frac{v - u}{t} \: \\ \\ a = \frac{25 - 5}{20} \\ \\ a = \frac{20}{20} \: \: \: \: \: \: \\ \\a = 1 \: \: m {s}^{ - 2}$

HOPE IT HELPS TO U