Question

Q2
An 80 kg person is parachuting and is experiencing a
downward acceleration of 2.8 m s-2. The mass of the
parachute is 5 kg. The upward force on the open parachute is
(Take g = 9.8 m s-2)
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595 N
675 N
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Answer 1

Answer:

Let:

m be the mass of the parachute,

M be the mass of the person,

P be the upward force on the parachute from the air,

T be the tension in the parachute cord,

F be the downward force on the parachute from the person,

g be the acceleration due to gravity,

a be the downward acceleration of the person and parachute.

For the parachute:

T + mg - P = ma ...(1)

For the person:

Mg - T = Ma ...(2)

(a)

Adding (1) and (2) to eliminate T:

(M + m)g - P = (M + m)a

P = (M + m)(g - a)

= (80 + 5)(9.8 - 2.5)

= 620.5 N

Explanation:

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