Question

Q2) an arrow 2.5 cm high is placed at a distance of 25 cm from a diverging mirror of focal length 20 cm. Find the nature, position and size of the image formed.

Answer 1

An arrow 2.5 cm high is placed at a distance of 25 cm from a diverging mirror of focal length of 20 cm-find the nature, position and size of the image formed. Hence the image will be formed at 11.11 cm behind the mirror, which will be virtual, erect and of 1.11cm size

Answer 2

Answer:

h1 = +2.5cm

u = -25cm

f = +20cm

1/f = 1/v + 1/u

1/20 = 1/v -1/25

1/v = 1/20 + 1/25

1/v = 9/100

v = +11.11 cm

m = h2/h1 = -v/u

h2/2.5 = -11.11/-25

h2 = +1.11 cm