Question

Q2 B) Solve any four of the following.
1) Obtain the quadratic equation if its roots are -3, -7.​

Answer 1

Step-by-step explanation:

let the given roots be a and b

a= -3 and b= - 7

therefore, formula of quadratic equation is

x^2-(a+b)x+a×b =0

x^2 -(-3-7)x + (-3×-7)=0

x^2 -(-10)x + 21=0

x^2 +10x + 21 = 0 .

Answer 2

Given question -: Obtain the quadratic equation if its roots are -3, -7.

Given

• Two roots
• $\alpha = - 3$

$\beta = - 7$

Now

$\alpha + \beta = - 3 + ( - 7) = - 10$

and

$\alpha \beta = - 3 \times ( - 7) = 21$

Required polynomial

${ {x}^{2} - ( \alpha + \beta )x + \alpha \beta }$

$\dashrightarrow \: {x}^{2} - ( - 10) x+ 21$

$\dashrightarrow \: {x}^{2} + 10x + 21$

Hope this will help you

Thank you..