Question

Q2 Derive expression for maximum work​

Answer 1

Here work done is calculated with the help of

Work = Pressure * change in volume

Work = -(-P – dP) – dV

Work = -(-PdV – dPdV)

For the expansion of the gas, the expansion will

be taken into consideration, so integrate the over equation,

Integrate to o to wmax dw = integrate to v1 to v2 PdV

Ideal gas, P = nRTN

Integrate o to wmax dw = integrate v1 to v2 RTN dt

On calculation, Wmax = -4.606 RT Log10 (V2/1)

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