Question

Q2 fast kal exam h yaar

Answer 1

Angle AOB= 180-50-40 ( Sum of angles of a triangle)
Angle OCD= 40 (Being alternate angles)
Angle ODC = 50 (Being alternate angles)

Answer 2

Answer:

A D = A A = 50° (alternate angle)

A C = A B = 40° (alternate angle)

A AOB = 180°- (40° + 50°) = 180°- 90° = 90° (angle sum property)

A COD = A AOB = 90° (vertically opposite angle)