Q2. Find all the zeroes of 2x
- 3x - 3x² + 6x-2, if two of its zeroes are 1
and
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2/3, 1 are the roots
Step-by-step explanation:
2x- 3x - 3x² + 6x-2=0
-3x^2+5x-2=0
3x^2-5x+2=0
a=3, b=-5, C=2
one of zero= 1
product of roots = C/a= 2/3
other root = C/a= 2/3
OR
2x- 3x - 3x² + 6x-2=0
-3x^2+5x-2=0
3x^2-5x+2=0
3x^2-3x-2x+2=0
3x(x-1)-2(x-1)=0
(3x-2)(x-1)=0
(3x-2) =0 (x-1)=0
3x=2 X=1
X=2/3 X=1
Other root = 2/3
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