Q2. Find LB and Lc of a parallelogram ABCD. If LB= (4x-5)° and LD=*(3x+10)°
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Answer:
In ∥gm opposite angles are supplementary.
Therefore,
∠B+∠D=180
∘
2x+25+3x−5=180
∘
x=
5
180−20
=32
∠B=2x+25=(2∗32)+25=89
∘
∠D=3x−5=(3∗32)−5=91
∘
solution
rizikasiddhi40:
why is this so complicated
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