Q2. Find the area of a triangle three sides of which 18 cm, 10 cm and 14 cm.
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Answer:
Area = 69.65
Step-by-step explanation:
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Answer:
here AB=18 cm
BC =10 cm
AC =14cm
semiperimeter = AB+BC+CA/2
= 18+10+14/2
= 42/2
= 21cm
Now by herons formula
area= √s(s-a)(s-b)(s-c)
=√21(21-18)(21-10)(21-14)
=√21 (3) (11) (7)
=√3×7×3×11×7
=3×7√11
=21√11
=21×3.31
=69.64 answer
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