Question

Q2: Find the output of the following pseudo-code
Integer value, n
Set value = 1, n = 45
while(value less than equal to n)
value = value << 1
end loop
Print value
​

Answer 1

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Answer 2

Answer:64

Explanation: Here, the left shift operation pushes the values towards the left once; when 1 is left-shifted the value that we will be obtaining will always be 2 to the power something. When one is converted in the beginning and not shifted the value will be 2^0 which is 1. The next iteration will be pushed one place towards the left, therefore the value now will be 2^1 which is 2; this will go on happening until the value stored is greater than 45. The value which is greater than 45 in 2 powers is 64. Now the loop terminates and the last value stored in the variable is 64 and the same will be printed.