Question

Q2.Find the output of the following
Text=”gmail@com”
L=len(Text)
ntext=” “
For i in range (0,L):
If text[i].isupper():
ntext=ntext+text[i].lower()
elif text[i].isalpha():
ntext=ntext+text[i].upper()
else:
ntext=ntext+’bb’

Answer 1

Answer:

ntext= GMAILbbCOM

Explanation:

the first line checks if the character at ith position is in upper case

in this case no

then it checks if the character is alphabet

in this case yes

so it is converted to capital

when it reaches @ sign it satisfies the last condition and

@ is replaced by bb

at

i=0 the value stored is g

i=1 the value stored is m

.                                      a

.                                        i

.

.

.

i=8 the vale storedis m