Question

Q2 Find the roots of quadratic equation by factorization method: √2x +7x+5√2=0​

Answer 1

✅verified answer

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Answer 2

Answer:

$-\sqrt{2}$ and $\frac{-5\sqrt{2}}{2}$

Step-by-step explanation:

$-> \sqrt{2}x^2+7x+5\sqrt{2}=0\\=> \sqrt{2}x^2+(5+2)x+5\sqrt{2}=0$...................................[By Mid-term splitting]

$=> \sqrt{2}x^2+5x+2x+5\sqrt{2}=0\\=> \sqrt{2}x(x+\sqrt{2}) + 5(x+\sqrt{2})=0\\=> (x+\sqrt{2})(\sqrt{2}x+5)=0$

1) $x = -\sqrt{2}$

2)$x=\frac{-5}{\sqrt{2}}$...............................[If you want to rationalize it, just multiply by $\frac{\sqrt{2}}{\sqrt{2}}$]

∴ $x= \frac{-5\sqrt{2}}{2}$, .......... By the way, $\frac{-5}{\sqrt{2}}$ is also correct.

So, the two roots are >>>> $-\sqrt{2}$ and $\frac{-5\sqrt{2}}{2}$.

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