Question

Q2 Find the value of k so that the following system of equations has no solution
3x-y-5= 0.6x-2y+k=0​

Answer 1

Answer:

K is not= -10

Step-by-step explanation:

the given system of equations:

3x-y-5=0and 6x-2y+k=0

these equations are of the following form a1x+b1y+c1=0, a2x+b2y+c2=0

where a1=3,b1=-1,c1=-5 and a2=6,b2=-2,c2=k

in order that the given system has no solutions

a1/a2=b1/b2is not =c1/c2

3/6=-1/-2is not = -5/k

-1/-2is not =-5/k

k is not=-10