Question

Q2. Find the value of the polynomials (i) P(x) = 3x ^ 3 - 4x + sqrt(4) at at x = 2​

Answer 1

Answer:

3(2)³-4(2)+2

= 24-8+2

= 18

Answer 2

Given

we have given function p(x) = 3x³-4x +√ 4

To Find

we have to find p(x) at x = 2

$\sf\huge {\underline{\underline{{Solution}}}}$

We have given a function p(x)= 3x³-4x+√4

At x=2 ,just put the given X's value into the f(x)

Note : Any change in p(x) will cause a change in the function.

Now ,our function is p(x) and we have to find p(2) now compare the coefficient of p(x) with p(2) , we find x=2

So,we have to find the value of p(x) at x=2

at x= 2

p(x)=> 3x³-4x+√4

=> 3(2)³-4(2)+2

=> 3*8-8+2

=> 24-8+2

=> 16+2

= 18

Therefore ,p(2) is 18

Extra information=>

➥The above function is a cubic equation as highest power is 3.

➥p(x)=y here ,f is the function and x is an input which gives output say 'y'.

➥We can find infinite number of output of p(x) by putting infinite number of values into p(x).