Question

Q2. Find the value of 'X'if
(2/3) (3/2)27/8​

Answer 1

Answer:

Step-by-step explanation:

or, (2√3)x = 1728 = 26 ∙ 33 = 26 ∙ (√3)6 or, (2√3)x ... 7[log(2 ∙ 5) - log32] + 3[1og34 - log(5 ∙ 24)] - 2[log52 - log(3 ∙ 23)] = 7[log 2 + log 5 ... If log10 2 = 0.30103, log10 3 = 0.47712 and log10 7 = 0.84510, find the values of (i) log10 45