Question

Q2) Find the zeroes of the quadratic polynomial x +7x+10, and verify the
relationship between the zeroes and the coefficients.​

Answer 1

Answer:

X+7x+10

8x+10

x=10×8

X=80

Answer 2

Answer:

the zeroes of the polynomial are -2 and -5.

Step-by-step explanation:

$Given \ polynomial, \ x^{2} +7x+10 = 0 \\\\ => x^{2} +7x+10 = 0 \\=> x^{2} +2x+5x+10 = 0 \\=>x(x+2) +5(x+2) = 0 \\=>(x+2)(x+5)=0 \\=> x =-2 \ (or) \ x=-5 \\\\ The \ zeroes \ of \ the \ polynomial \ are -2 \ and \ -5.$

$RELATIONSHIP \ BETWEEN \ ZEROES \ AND \ COEFFICIENTS:$

$=>Sum \ of \ zeroes \ = -2-5 \\\\ = -7 \\\\ =\frac{-(x \ coefficient)}{x^{2} \ coefficient} \\\\\\ =>product \ of \ zeroes = (-2)(-5) \\\\ =10$

$= \frac{(constant)}{x^{2} \ coefficient}$

$HOPE \ IT \ HELPS..!$