Q2. Find value of x if P(0,2) is equidistant from (3,x) and (x,5).find value of x.( by distance formula )
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Step-by-step explanation:
Let the three points be P(0,2), A(3, K) and B(k,5).
and, AP=BP
⇒AP^2=BP^2
⇒(3−0)^2+(k−2)^2=(k−0)^2+(5−2)^2
⇒9+k+4−4k=k^2+9
⇒4k=4
⇒k=1
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