Question

Q2. Find "x" if, (2/3)^-x+ (2/3)^-4 = (2/3)^5

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Answer 1

Answer:

$(\frac{2}{3} ) {}^{ - x} + ( \frac{2}{3} ) {}^{ - 4} = ( \frac{2}{3} ) {}^{5}$

- x + -4 = 5

-x = 5+4

-x = 9

x = -9

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