Question

Q2. For what the value of n, are the nth terms of two APs 63,65,67….. and
3,10,17,.....are equal?

Answer 1

Answer:

For the 1st ap,

a=63, d=2

For the 2nd ap,

a1=3, d1=7

Therefore,

an=a1n

=> a+(n-1)d = a1+(n-1)d1

=> 63+(n-1)2 = 3+(n-1)7

=> 63+2n-2 = 3+7n-7

=> 61+2n = 7n-4

=> 5n = 65

=> n=13