Question

Q2 from this photo pls help me

Answer 1

Answer:

2)sin A = √3cosA

sinA/cosA = √3

tanA = √3. [tan X = sin X /cos X]

tan A = tan 60°

A = 60°.

3)sin X + cos X = 1

squaring on both sides ,

sin²x + cos²x + 2 sin X · cos X = 1

we know that sin²x + cos²x = 1.

1 + 2 sin X · cos X = 1

2 sin X · cos X = 0

sin X · cos X = 0/2

sin X · cos X = 0.

hope it helps you