Q2. If -2 and 3 are the zeroes of the quadratic polynomial x? + (p+1)x+4, then find the
values of p arda.
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Answer:
x = -2
(-2)2+(p+1)(-2+4=0
4-2p-2+4=0
8-2p-2=0
6-2p = 0
2p = 6
p = 3
x = 3
(3)2+(p+1)(3)+4=0
9+3p+3+4=0
16+3p = 0
p = 16/3
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