Question

Q2. If P = {x:x < 7, x ∈ N} and Q ={x: x²< 49,x ∈ N},then

P ⊂ Q

Q ⊂ P

P = Q

P∪{7} = Q

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Answer 1

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

TO CHOOSE THE CORRECT OPTION

$\sf{If \: P = \{ \: x : x < 7, x \in \N \: \} \: and \: Q= \{ \: x : {x}^{2} < 49, x \in \N \: \} \: }$

Then

• P ⊂ Q

• Q ⊂ P

• P = Q

• P ∪ {7} = Q

CONCEPT TO BE IMPLEMENTED

SUBSET : Let S be a set. Then a set T is said to be a subset of S if every element of T is an element of S

$\sf{We \: write \: it \: as \: \: \: \: T \subset \: S}$

EQUAL SET : Two set S and T are said to be Equal Set if every element of S is a element of T and every element of T is an element of S

We write it as S = T

CALCULATION

Here

$\sf{ P = \{ \: x : x < 7, x \in \N \: \} \: \: }$

So

$\sf{P = \{ \: 1, 2,3,4,5,6 \: \} }$

Again

$\sf{ Q= \{ \: x : {x}^{2} < 49, x \in \N \: \} \: }$

So

$\sf{Q = \{ \: 1, 2,3,4,5,6 \: \} }$

SO every element of P is a element of Q and every element of Q is an element of P

Hence P = Q

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If n(A) = 300, n(A∪B) = 500, n(A∩B) = 50 and n(B′) = 350, find n(B) and n(U)

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