Question

Q2. If the sum of the zeroes of the quadratic polynomial
k y2 + 2y - 3k is - 6, then find value of k.​

Answer 1

Answer:

f(t)=Kt

2

+2t+3K

Let roots be α,β

α+β=−

K

2

αβ=

K

3K

According to question, α+β=αβ

∴−

K

2

=

K

3K

∴K=−

3

2

Answer 2

Required Answer:-

Given:

• The sum of the zeroes of the Quadratic polynomial ky² +2y - 3k is -6.

To find:

• The value of k.

Solution:

Given equation,

➡ ky² + 2y - 3k = 0

Comparing with ax² + bx + c = 0, we get,

➡ a = k

➡ b = 2

➡ c = -3

We know that,

Sum of zeros = -b/a

➡ -6 = -2/k

➡ -6/-2 = 1/k

➡ 3 = 1/k

➡ k = 1/3

Hence, the value of k is 1/3

Hence, the required quadratic equation is,

➡ 1/3y² +2/3y - 3 = 0

Answer:

• The value of k is 1/3.