Question

q2 im having doubt please help me with it​

Answer 1

Analysis→

Here the question conveys that 200kg of water is to be lift to a vertical height of 15m. And we've to find the amount of work done to life it (assuming g=10m/s²). And we know that:-

$\dashrightarrow\rm{W=F\times s}$

$\dashrightarrow\rm{ F=m\times a\qquad\big[a=g\big]}$

$\therefore\rm{W=mgh\qquad\big[s=h\big]}$

Given→

• Mass of water(m)=200kg
• Heigt(h)=15m
• g=10m/s²

To Find→

The work done to life the water to the given height.

Answer→

$\large{\underline{\boxed{\leadsto{\rm{W=mgh}}}}}$

$\implies\rm{W=mgh}$

$\implies\rm{W=200kg\times10\frac{m}{s}\times15m}$

$\implies\rm{W=2000\times15}$

$\implies\rm{W=30,000Joules}$

${\boxed{\boxed{\implies{\bf{W=30,000J;3\times10^4J\checkmark}}}}}$

☞ Hence the work done required to life 200kg of water to a height of 15m is 30,000Joules or $\rm{3\times10^4Joules}$ which is the required answer.

HOPE IT HELPS.