Q2) in an isosoples triangle, the vertex angle is 30" What are the base angles of the triangle
03) PQR is a triangle right angled at P. PQ = 14cm and PR 50 find qr
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Q2 explanation : let the name of triangle be ABC
vertex angle (c) = 30
we know that A = B ( opposite angles of equal sides are equal )
so,let the A and B be x
A+B+C = 180°
x + x + 30= 180°
2x + 30° = 180°
2x = 180°-30°
2x = 150°
x = 150/2
x = 75°
A = B = 75°
so, vertex angle is 75°
Q3 Explanation: By Pythagoras theoram
QR^2 = PR^2+QR^2
OR = 14^2+50^2
OR = 196+2500
QR^2 = 2696
QR = root 2696
sorry, I try to do 3 que but I cant
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