Q2) Number of lines passing through five points such that no three of them are collinear is *
1 point
10
20
5
8
Answers
Answered by
1
Answer:
Correct option is
A
10
Step-by-step explanation:
We know that a line consist minimum tow point, but five point are colinear
∴ total number of lines is 5×2=10
hope it was helpful
Answered by
3
Answer:
the lines are AB, AC, AD, AE, BC, BD, BE, CD, CE, DE. So that makes 10 lines.
Hope it helps!
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