Q2.Pen down thirty new words and their meanings from the literature-based lesson enlisted below:The Tiny teacher
b). Three questions
c). Bringing up Kari
d). The squirrel
someone answer
Answers
We can learn team work from ants as they do their work by sharing and contributing without interference in other’s work. We can learn hard work as ants spend most of their time in doing their respective jobs without hesitation. We can learn discipline as ants live a disciplined life and always follow the rules of their group and are loyal towards it.
Answer:
Given :-
It is given to find whether which fraction should be added to \sf 5\frac{4}{15}5154 to get \sf 12\frac{3}{5}1253 .
Answer :-
Heyo! You can use the following Solution below;
Let's first solve the mixed fractions to improper fractions.
\begin{gathered} \sf{5 \frac{4}{15} } \: \: and \: \: 12 \frac{3}{5} \\ \end{gathered}5154and1253
\begin{gathered} \leadsto \sf{ \frac{79}{15} } \: \: and \: \: \frac{63}{5} \\ \end{gathered}⇝1579and563
⠀2. Now, we can form a linear equation ⠀⠀⠀to find the number which must be ⠀⠀⠀added to \sf \frac{79}{15}1579 to ⠀⠀⠀get \sf \frac{63}{5}563 .
\begin{gathered} \sf{x + \frac{79}{15} = \frac{63}{5} } \\ \end{gathered}x+1579=563
\begin{gathered} \leadsto \sf{x = \frac{63}{5} - \frac{79}{15} } \\ \end{gathered}⇝x=563−1579
\begin{gathered} \leadsto \sf{x = \frac{63 - 79}{30} } \\ \end{gathered}⇝x=3063−79
\begin{gathered} \leadsto \sf{ x = \frac{ - 16}{30} } \\ \end{gathered}⇝x=30−16
\begin{gathered} \leadsto \sf{x = \frac{ \cancel{ - 16}}{ \cancel{30}}} \\ \end{gathered}⇝x=30−16
\begin{gathered} \leadsto \sf{x = \frac{ - 8}{15} } \\ \end{gathered}⇝x=15−8
\dashrightarrow⇢ Hence, \bf \frac{-8}{15}15−8 must be added to \sf{5\frac{4}{15}}5154 to get \sf{12\frac{3}{5}}1253 .
\begin{gathered} \\ \end{gathered}
Given :-
It is given to find whether which fraction should be added to \sf 5\frac{4}{15}5154 to get \sf 12\frac{3}{5}1253 .
Answer :-
Heyo! You can use the following Solution below;
Let's first solve the mixed fractions to improper fractions.
\begin{gathered} \sf{5 \frac{4}{15} } \: \: and \: \: 12 \frac{3}{5} \\ \end{gathered}5154and1253
\begin{gathered} \leadsto \sf{ \frac{79}{15} } \: \: and \: \: \frac{63}{5} \\ \end{gathered}⇝1579and563
⠀2. Now, we can form a linear equation ⠀⠀⠀to find the number which must be ⠀⠀⠀added to \sf \frac{79}{15}1579 to ⠀⠀⠀get \sf \frac{63}{5}563 .
\begin{gathered} \sf{x + \frac{79}{15} = \frac{63}{5} } \\ \end{gathered}x+1579=563
\begin{gathered} \leadsto \sf{x = \frac{63}{5} - \frac{79}{15} } \\ \end{gathered}⇝x=563−1579
\begin{gathered} \leadsto \sf{x = \frac{63 - 79}{30} } \\ \end{gathered}⇝x=3063−79
\begin{gathered} \leadsto \sf{ x = \frac{ - 16}{30} } \\ \end{gathered}⇝x=30−16
\begin{gathered} \leadsto \sf{x = \frac{ \cancel{ - 16}}{ \cancel{30}}} \\ \end{gathered}⇝x=30−16
\begin{gathered} \leadsto \sf{x = \frac{ - 8}{15} } \\ \end{gathered}⇝x=15−8
\dashrightarrow⇢ Hence, \bf \frac{-8}{15}15−8 must be added to \sf{5\frac{4}{15}}5154 to get \sf{12\frac{3}{5}}1253 .
\begin{gathered} \\ \end{gathered}
Given :-
It is given to find whether which fraction should be added to \sf 5\frac{4}{15}5154 to get \sf 12\frac{3}{5}1253 .
Answer :-
Heyo! You can use the following Solution below;
Let's first solve the mixed fractions to improper fractions.
\begin{gathered} \sf{5 \frac{4}{15} } \: \: and \: \: 12 \frac{3}{5} \\ \end{gathered}5154and1253
\begin{gathered} \leadsto \sf{ \frac{79}{15} } \: \: and \: \: \frac{63}{5} \\ \end{gathered}⇝1579and563
⠀2. Now, we can form a linear equation ⠀⠀⠀to find the number which must be ⠀⠀⠀added to \sf \frac{79}{15}1579 to ⠀⠀⠀get \sf \frac{63}{5}563 .
\begin{gathered} \sf{x + \frac{79}{15} = \frac{63}{5} } \\ \end{gathered}x+1579=563
\begin{gathered} \leadsto \sf{x = \frac{63}{5} - \frac{79}{15} } \\ \end{gathered}⇝x=563−1579
\begin{gathered} \leadsto \sf{x = \frac{63 - 79}{30} } \\ \end{gathered}⇝x=3063−79
\begin{gathered} \leadsto \sf{ x = \frac{ - 16}{30} } \\ \end{gathered}⇝x=30−16
\begin{gathered} \leadsto \sf{x = \frac{ \cancel{ - 16}}{ \cancel{30}}} \\ \end{gathered}⇝x=30−16
\begin{gathered} \leadsto \sf{x = \frac{ - 8}{15} } \\ \end{gathered}⇝x=15−8
\dashrightarrow⇢ Hence, \bf \frac{-8}{15}15−8 must be added to \sf{5\frac{4}{15}}5154 to get \sf{12\frac{3}{5}}1253 .
\begin{gathered} \\ \end{gathered}