Physics, asked by IntelligentBrain, 10 months ago

Q2 PLZ.....................................................

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Answered by DrStudy
1

Answer:

initial velocity= 0

time= 5.21 secs

distance= 110 m

Let the final velocity be v.

distance= velocity×time

110 = v× 5.21

=> 110/5.21= v

=> 21.11= v

acceleration= v-u/t

= 21.11-0/5.21

= 21.11/5.21

= 4.05 m/s^2

Thus, the acceleration is 4.05 m/s^2.


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