Q2 PLZ.....................................................
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Answer:
initial velocity= 0
time= 5.21 secs
distance= 110 m
Let the final velocity be v.
distance= velocity×time
110 = v× 5.21
=> 110/5.21= v
=> 21.11= v
acceleration= v-u/t
= 21.11-0/5.21
= 21.11/5.21
= 4.05 m/s^2
Thus, the acceleration is 4.05 m/s^2.
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