Computer Science, asked by yuvrajsandhu979, 2 months ago

Q2 Pocket expenses of a class in a college are shown in the following frequency distribution:
Pocket expenses Number of students
0-200
33
200-400
74
400-600
170
600-800
88
800-1000
76
1000-1200
45
Please tell fast​

Answers

Answered by Abhaysingh8269
0

Answer:

1=200

2=400

3=200

4=200

Answered by temporarygirl
4

Hola mate

Here is your answer -

(0-200) = (0+200) = 200 = (200÷2) = 100

(200-400) = (200+400) = 600 = ( 600÷2) = 300

(400-600) = (400+600) = 1000 = ( 1000÷2) = 500

(600-800) = (600+800) = 1400 = ( 1400÷2) = 700

(800-1000) = (800+1000) = 1800 = (1800÷2) = 900

(1000-1200) = (1000+1200) = 2200 = (2200÷2) = 1100

(1200-1400) = (1200+1400) = 2600 = (2600÷2) = 1300

So the medians are 100, 300, 500, 700, 900, 1100, 1300.

medians no. of the students the multiplication of median and std's no.

100 33 3300

300 74 2220

500 170 85000

700 88 61600

900 76 68400

1100 44 48400

1300 25 32500

➡sum of the student's no. = 510

➡sum of the median which we got after multipication = 301,400

➡So, the mean is = (301,400 ÷ 510)

= 590.98

Hope this helps you!

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