Q2. Show that -1, 3 and 6 are zeroes of the polynomial p(x) = x3 – 8x2 + 9x + 18. Also verify
the relationship between the zeroes and the coefficients of p(x).
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Answer:
To verify ,You can put these values in the above equation and check whether the result is zero or not.
i.e.
p(-1) = 0
p(3) = 0
p(6) = 0
And we know the relationship between zeroes are
sum of zeroes = -b/a
product of zeroes = -d/a
sum of product of two zeroes = c/a
Now, we will check
-1+3+6 = -(-8)= 8
-1*3*6 = -18
(-1*3)+(3*6)+(-1*6)= 9.
Verified.
Step-by-step explanation:
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