Question

Q2. Show that -1, 3 and 6 are zeroes of the polynomial p(x) = x3 – 8x2 + 9x + 18. Also verify
the relationship between the zeroes and the coefficients of p(x).

Answer 1

Answer:

To verify ,You can put these values in the above equation and check whether the result is zero or not.

i.e.

p(-1) = 0

p(3) = 0

p(6) = 0

And we know the relationship between zeroes are

sum of zeroes = -b/a

product of zeroes = -d/a

sum of product of two zeroes = c/a

Now, we will check

-1+3+6 = -(-8)= 8

-1*3*6 = -18

(-1*3)+(3*6)+(-1*6)= 9.

Verified.

Step-by-step explanation: