Math, asked by rodinsing006, 5 hours ago

Q2. Solve the following

i) (2√5+3√3) + (3√5+ 4√3)

ii) 6√7 × 2√7

iii) 6√15÷3√5​

Answers

Answered by kananpuri5034
0

Answer:

i=23.3046955405 ok that much only

Answered by bagkakali
2

Answer:

I) (2√5+3√3)+(3√5+4√4)

=2√5+3√3+3√5+4√3

=5√5+7√3

ii) 6√7×2√7

=12×7

=84

iii)6√15÷3√5

=3×2×√5×√3÷3√5

=2√3

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