Math, asked by shayagole, 11 months ago

Q2. Sudhakar borrows Rs. 22500 at 10% per annum, compounded annually. If he repays

Rs.11250 at the end of first year and Rs.12250 at the end of the second year, find the amount of

loan outstanding against him at the end of the third year.​

Answers

Answered by efimia
27

Answer:

Rs6447 has to be paid after end of third year.

Step-by-step explanation:

Principle amount of money=Rs22500.

Rate of interest=10%

Time =3years.

Amount of money after three years,

=22500(1+10/100) ^3

=22500(1.1) ^3

=29947.

Money paid after first year = Rs 11250.

Money paid after second year= Rs12250.

Total money paid in 2 years =(11250+12250) = Rs. 23500

Money that has to be paid after 3years= (29947-23500) =Rs 6447.

Answered by kanishkanitin
29

Answer:

hey there.. here is your answer

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