Question

Q2: The launching mechanism of a toy gun consists of a spring of unknown spring constant (Fig.
8.11a). When the spring is compressed 0.120 m, the gun, when fired vertically, is able to launch a
35.0-g projectile to a maximum height of 20.0 m above the position of the projectile before firing.
(a) Neglecting all resistive forces, determine the spring constant k.​

Answer 1

Answer:

the answer is this - 10m/s²

Answer 2

Answer: The value of spring constant is 972.22 N/m

Explanation:

Let the spring constant be k

When the spring is compressed, potential energy is stored in the spring. When the spring is set free, the potential energy stored gets converted into Kinetic energy.

As the particle goes up , its kinetic energy starts getting converted into gravitational potential energy.

At the highest point , all of its energy is in form of gravitational potential energy and kinetic energy is 0

Therefore,

$\frac{kx^{2} }{2} = mgh\\k = \frac{2mgh}{x^{2} }$

k  = (2 × 35 × 10⁻³ × 10 × 20) / ( 0.12² )

k = 972.22 N/m

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