Q2. The ratio between marked price of a same watch in two shops P and Q is 7:
5. In shop P watch available at two successive discounts of 10% & 25%, while in
shop Q watch available at two successive discounts of d% and 10%. If selling
price of watch at shop Q is less than that of selling price of watch at shop P by
44/105 of the selling price of watch at shop P, then find the value of 'd' ?
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The value of d is 39
Step-by-step explanation:
Ratio of marked price in shop P and Q =7:5
Let the prices be 7x and 5x
Selling Price of shop P = 7x(1-0.1)(1-0.25)=7x*0.9*0.75
Selling price of Shop Q = 5x(1-0.1)(1-d/100)=5x(0.9)(1-d/100)
According to the question
7x*0.9*0.75 - 5x(0.9)(1-d/100) = 7x*0.9*0.75*44/105
=>7x*0.9*0.75-7x*0.9*0.75*44/105 =5x(0.9)(1-d/100)
=>7*0.75 - 7*0.75*44/105 = 5*(1-d/100)
=> 7*0.75(105-44)/105 = 5*(1-d/100)
=>7*75*61/(105*100)=5*(1-d/100)
=>1-d/100 = 61/(20*5)
=>d/100 = 1-61/100
=>d=39
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