Question

Q2. The shadow of a tree on the ground is found to be 20 m when the sun rays meet the ground at an angle of 30°. Find the height of the tree.
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Answer 1

Answer:

height of tree$=20\sqrt{3} m$

Step-by-step explanation:

angle of elevation θ=30°

base=20m

height =x

using trigonometry,

tanθ$=\frac{perpendicular}{base}$

tan60°$=\frac{x}{20}$

$\sqrt{3} =\frac{x}{20}$

$x=20\sqrt{3}$

hence, height of tree $=20\sqrt{3} m$

Answer 2

Answer : The height of the Tree is 11.55m

Step-by-step explanation :

Please see the attached document for figure :

Given :. AB = 20m

∠BAC = 30°

To find : Height of the Tree ( BC ) = ?

Let the Height of the Tree be ' h '

Therefore from the figure ,

tan 30° = BC / AB

1 / √3 = h / 20

1 /√ 3 × 20 = h

h = 11.55 m

Therefore the height of the Tree is 11.55m