Q2.The speedometer readings of a car are shown below. Find the acceleration of the car and
its displacement.
Time Speedometer
9:25 a.m. 36 km/h
9:45 a.m. 72 km/h
Answers
Step-by-step explanation:
Answer:
The Speedometer readings are given below :
Time — Speed
9.25 AM — 36 km/h
9.45 AM — 72 km/h
Let us find :
Time = 45 - 25 = 20 m = 20 × 60 = 1,200 s
Initial Speed = 36 km/h = 36×5/18 = 180/18 = 10 m/s
Final Speed = 72 km/h = 72×5/18 = 360/18 = 20 m/s
So, Acceleration of the car = (v-u)/t
⇒ a = (20-10)/1,200
⇒ a = 10/1,200
⇒ a = 1/120
⇒ a = 0.008 m/s²
Now, Displacement of the car :
Using the second equation of motion -
⇒ s = ut + ½at²
⇒ s = 10*1,200 + ½*0.008*(1,200)²
⇒ s = 12,000 + ½*0.008*1,200*1,200
⇒ s = 12,000 + 600*1,200*0.008
⇒ s = 12,000 + 4.8*1,200
⇒ s = 12,000 + 5,760
⇒ s = 17,760 m
Hence,
The Acceleration of the car = 0.008 m/s².
The Displacement of the car = 17,760 m.
Answer:
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Step-by-step explanation:
Given:
Time = t= 9.45 -9.25=20min= 20x60 seconds
Initial velocity = 36km/h = 36x 5/18=10 m/s
Final velocity = V= 72km/h=72x 5/18=20m/s
Acceleration= a=V-u/t
=20-10/20x60
=10/20x60
=1/120
=0.008m/s2
THEREFORE acceleration of the car is 0.008m/s2
From Second equation of motion:
V^2-u^2=2as
S=V^2-u^2/2a
S=(20×20)-(10×10)/2*0.008
S=(400_100)/2*0.008
=300/2×0.008 =150/0.008 =150*1000/8 =18.75x 1000 =1875000/100=18750m Magnitude of displacement is 18750m
and if u don't understand it I will atach
