Question

Q2.The speedometer readings of a car are shown below. Find the acceleration of the car and

its displacement.

Time Speedometer

9:25 a.m. 36 km/h

9:45 a.m. 72 km/h​
​

Answer 1

Answer:

It is given that u=36km/h

V= 72km/h

We have to convert it into m/s ao we will multiply it with 5/18

U=36×5/18=10

V=72×5/18=20

So acceleration =v-u/t

= 20-10/t

The time will be 9:45-9:25=20min

So we will convert it into second

= 20×60

a=20-10/20×60

=10/20×60

1/120

From newtons 2nd law

V^2-u^2=2as

S=v^2-u^2/2a

=400-100×120/2

=18000m/s

Explanation:

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Answer 2

Answer:

Let

u=36km/h

V= 72km/h

We should convert it into m/s and multiply with 5/18

U=36×5/18=10

V=72×5/18=20

The time will be 9:45-9:25=20min

converting it into sec

we get 1/120

from Newton"s third law

v^2-u^2=2as

s=v^2-u^2/2a

s=400-100×120/2

s= 18000m/s .

Hope it helps u mate