Question

Q2.The sum of the present ages of a mother and her daughter is 60

years. Six years ago, mother’s age was five times the age of the

daughter. Find their present ages.​

Answer 1

$\huge\sf\purple{\underline{Question}}$

Q2. The sum of the present ages of a mother and her daughter is 60 years. Six years ago, mother’s age was five times more than the age of the daughter. Find their present ages.

$\huge\rm{\fcolorbox{black}{lavender}{\purple{Solution:-}}}$

$\rm\red{\underline{Ans. }} \textrm{ \: Let daughter's age be 'f' years} \\ \therefore\textrm{Mother's age is f+5 years} \\ \therefore\textrm{Sum of their ages is 60 years} \\ \therefore\textrm{f+f+5 = 60} \\ \therefore\textrm{2f+5 = 60} \\ \therefore\textrm{2f = 60-5} \\ \therefore\textrm{2f = 55} \\ \boxed{\therefore{f=\frac{55}{2}}} \\ \therefore\rm{Daughter's \: age \: is \: f = \frac{55}{2} \: and \: Mother's \: age \: is \: f+5 = \frac{55}{2} + 5}$

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Answer 2

Answer:

Hey the current age of mom is 46 and her daughter is 14

Step-by-step explanation:

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