Question

Q2) The taxi fare in the city is as follows for the first 1st km the fare is
*.40 and for the subsequent distance it is R.20 per kilometre. Write a
linear equation for the given information by taking distance covered
as x km and total fare as rs.y

please answer this question fast​

Answer 1

Answer:

40+20x=y

Let 40rupees be fix for 1km

Answer 2

Step-by-step explanation:

given ,

taxi fare for 1st km is =Rs 40

for subsequent km is 20 rupees

so the sequence forms an A.P with

40,60,80,.........

so the taxi fare for nth kilometer is an

=40+(n-1)20

40+20n-20

20+20n so the taxi fare is depends on the distance 'n' km travelled so total fare y is

y=20x+20