Math, asked by lodaaram12, 10 months ago

Q2. The value of k for which the roots of the equation x^2+4x+k=0 are real is 1.k=4 2.k˂4 3.k˃4 4.k⦤4

Answers

Answered by bktbunu
1

Answer:

4.k⦤4

Step-by-step explanation:

x^2+4x+k=0

For real roots, D>=0

D=4^2-4×1×k=16-4k>=0

4k <= 16

k <= 4

Similar questions