Q2. The value of m which makes the points (0,0), (2m, -4), and (3,6) collinear is __________ * 1 point 1 0 -1 2
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Answer:
-1
Step-by-step explanation:
use slope concept
slope of line AC = slope of line BC
6-0/(3-0) = 6-(-4) / (3-2m)
2 = 10/(3-2m)
3-2m= 5
2m=-2
m= -1
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