Question

Q2 The zeroes of the quadratic polynomial x² + 99x + 127 are A both positive B both negative С one positive and one negative D both equal?​

Answer 1

Step-by-step explanation:

we can check this by using discrimanat formula

$d = {b}^{2} - 4ac$

so here a = 1 , b = 99 , c = 127

so putting the values

$d = {99}^{2} - 4(1)(127)$

$d = 9801 - 508 \\ = 9293$

so here d is positive and we know

I. d > 0,2 distinct real roots

ii. d = 0 , two equal real roots

iii. d<0 , no real roots

here d is greater than 0 , so 2 distinct real roots.

and we can say that all coefficient are positive so the roots will be negative

therefore the answer will be B. both negative