Q2 There are two point charges thuc and
-2uc, placed at some distance. The ratio
of magnitude of electzostalic forces acting
on them resp. will be
01:2 ② 2:1 ③ 1:4 4 1:1
Answers
Explanation:
Given:
Two charges Q1, Q2.
Distance between Q1 and Q2 = R .
Magnitude of force on Q2 = F
Given:
Represent graphically the variation of force f on Q2 with
(i) magnitude of Q2
(ii) distance from Q1
(iii) distance with 1/r^2
Solution:
We know that the Coloumbic force of attraction between two charges Q1 and Q2, separated by a distance R is given by,
F = Q1Q2/4π∈R²
Let 1/4π∈ = K, a constant = 9 x Nm²/C²
Consider F.
F = KQ1Q2/R²
We need to find variation of F with :
magnitude of Q2
F = (kQ1/R²) x Q2
Lets assume Q1, R are constant.
F α Q2 , directly proportional.
Hence F vs Q2 varitaion will be a straight line passing through origin.
Slope = KQ1/R²
2.distance from Q1 , R
F = (kQ1Q2) / R²
Lets assume Q1, Q2 are constant
F α 1/R²
F is inversely proportional to square of distance.
It will be a hyperbola.
3. with 1/R²
F α 1/R²
F is directly proportional to 1/R²
F vs 1/R² will be a straight line through origin
Slope = KQ1Q2
Hence we have represented graphically the variation of force f on Q2 with
(i) magnitude of Q2
(ii) distance from Q1
(iii) distance with 1/r^