Physics, asked by dubewarashish2, 9 months ago

Q2 There are two point charges thuc and
-2uc, placed at some distance. The ratio
of magnitude of electzostalic forces acting
on them resp. will be
01:2 ② 2:1 ③ 1:4 4 1:1​

Answers

Answered by piyushstar010180
0

Explanation:

Given:

Two charges Q1, Q2.

Distance between Q1 and Q2 = R .

Magnitude of force on Q2 = F

Given:

Represent graphically the variation of force f on Q2 with

(i) magnitude of Q2

(ii) distance from Q1

(iii) distance with 1/r^2

Solution:

We know that the Coloumbic force of attraction between two charges Q1 and Q2, separated by a distance R is given by,

F = Q1Q2/4π∈R²

Let 1/4π∈ = K, a constant  = 9  x Nm²/C²

Consider F.

F = KQ1Q2/R²

We need to find variation of F with :

magnitude of Q2

F = (kQ1/R²) x Q2

Lets assume Q1, R are constant.

F α Q2 , directly proportional.

Hence F vs Q2 varitaion will be a straight line passing through origin.

Slope = KQ1/R²

    2.distance from Q1 , R

F = (kQ1Q2) / R²

Lets assume Q1, Q2 are constant

F α 1/R²

F is inversely proportional to square of distance.

It will be a hyperbola.

    3. with 1/R²

F α 1/R²

F is directly proportional to 1/R²

F vs 1/R² will be a straight line through origin

Slope = KQ1Q2

Hence we have represented graphically the variation of force f on Q2 with

(i) magnitude of Q2

(ii) distance from Q1

(iii) distance with 1/r^

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