Q2. Using concepts of Vedic maths show simplification of these mathematical problems. 1) 8655675 x 9999999 2) 352132 x 11 3) 332241334 x 111 4) 65 x 45 5) 533532 x 77
Answers
Answer:
A) 8655675
B) 387352
C) 36878788074
Step-by-step explanation:
pls mark me as brainliest!!!
- 86556741344325
- 3873452
- 36878788074
- 2925
- 41081964
To Find :- Using concepts of Vedic maths show simplification of these mathematical problems :-
1) 8655675 x 9999999
2) 352132 x 11
3) 332241334 x 111
4) 65 x 45
5) 533532 x 77
Solution :-
1) 8655675 x 9999999
Concept when any number is multiply by 9, 99, 999, 9999 etc :-
- a × 9 = (a - 1)(10 - a)
- ab × 99 = (ab - 1)(100 - ab)
- abc × 999 = (abc - 1)(1000 - abc)
- abcd × 9999 = (abcd - 1)(10000 - abcd)
Example :-
→ 8 × 9 = (8 - 1)(10 - 8) = 72
→ 42 × 99 = (42 - 1)(100 - 42) = 4158
→ 375 × 999 = (375 - 1)(1000 - 375) = 374625
→ 6281 × 9999 = (6281 - 1)(10000 - 6281) = 62803719
using same concept we get,
→ 8655675 x 9999999
→ (abcdefg) × 9999999
→ (abcdefg - 1)(10000000 - abcdefg)
→ (8655675 - 1)(10000000 - 8655675)
→ 86556741344325 (Ans.)
2) 352132 x 11
Concept when any number is multiply by 11 :-
- ab × 11 = a(a + b)b
- abc × 11 = a(a + b)(b + c)c
- abcd × 11 = a(a + b)(b + c)(c + d)d
Example :-
→ 34 × 11 = 3(3 + 4)4 = 374
→ 236 × 11 = 2(2 + 3)(3 + 6)6 = 2596
→ 4875 × 11 = 4(4 + 8)(8 + 7)(7 + 5)5 = 4(12)(15)(12)5 = Starting from left now and taking carry in next we get = 4(12)(15 + 1)25 = 4(12 + 1)625 = (4+1)3625 = 53625
using same concept we get,
→ 352132 x 11
→ 3(3+5)(5+2)(2+1)(1+3)(3+2)2
→ 3873452 (Ans.)
3) 332241334 x 111
Concept when any number is multiply by 11 :-
- abc × 111 = a(a + b)(a + b + c)(b + c)c
- abcd × 111 = a(a + b)(a + b + c)(b + c + d)(c + d)d
- abcde × 111 = a(a + b)(a + b + c)(b + c + d)(c + d + e)(d + e)e
Example :-
→ 365 × 111 = 3(3+6)(3+6+5)(6+5)5 = 39(14)(11)5 = 39(14 + 1)15 = 39(15)15 = 3(9+1)515 = 3(10)515 = (3+1)0515 = 40515
using same concept we get,
→ 332241334 x 111
→ 3(3+3)(3+3+2)(3+2+2)(2+2+4)(2+4+1)(4+1+3)(1+3+3)(3+3+4)(3+4)4
→ 36878787(10)74
→ 3687878(7+1)074
→ 36878788074 (Ans.)
4) 65 × 45
Concept :-
- a5 × b5 = (a × b + 5)25 where (a + b) is equal to 10 .
Example (1) :-
→ 15 × 95
As we can see that 1 + 9 = 10 . So,
→ (1 × 9 + 5)25
→ (9 + 5)25
→ 1425
Example (2) :-
→ 25 × 85
since 2 + 8 = 10,
→ (2 × 8 + 5)25
→ (16 + 5)25
→ 2125
using same concept we get,
→ 65 × 45
since 6 + 4 = 10,
→ (6 × 4 + 5)25
→ (24 + 5)25
→ 2925 (Ans.)
5) 533532 x 77
Concept :-
- abc × 77 = (a × 7){(a + b)×7}{(b + c)×7}(c × 7)
Example :-
→ 123 × 77
→ (1×7){(1 + 2)×7}{(2 + 3)×7}(3 × 7)
→ 7(21)(35)(21)
→ 7(21)(35+2)1
→ 7(21)(37)1
→ 7(21+3)71
→ 7(24)71
→ (7+2)471
→ 9471
using same concept we get,
→ 533532 x 77
→ (5×7){(5+3)×7}{(3+3)×7}{(3+5)×7}{(5+3)×7}{(3+2)×7}(2×7)
→ (35)(56)(42)(56)(56)(35)(14)
starting from left side now and adding carry in next,
→ (35)(56)(42)(56)(56)(35 + 1)4
→ (35)(56)(42)(56)(56)(36)4
→ (35)(56)(42)(56)(56 + 3)64
→ (35)(56)(42)(56)(59)64
→ (35)(56)(42)(56 + 5)964
→ (35)(56)(42)(61)964
→ (35)(56)(42 + 6)1964
→ (35)(56)(48)1964
→ (35)(56 + 4)81964
→ (35)(60)81964
→ (35+6)081964
→ 41081964 (Ans.)
Learn more :-
Consider the sequence defined by ak=1/k2-k for k ≥ 1. Given that aM + aM + 1 + …………+ aN – 1=1/29 for positive integers M...
https://brainly.in/question/42384271
(c)
75. From a number M subtract 1. Take the reciprocal of
the result to get the value of 'N'. Then which of the
followi...
https://brainly.in/question/39499253